You are correct up to the point where you think the E field of all electrons points to the center. Actually, the electrons will all rush towards one end of the ring. There would then be an e field around the ring caused by the electrons, and an e field in the opposite direction caused by the EMF. When they will be equal, the current will stop and the ring will be like a capacitor under voltage.
I agree with you that "When they will be equal, the current will stop and the ring will be like a capacitor under voltage." In this case, the electric field on the surface of the wire is 0 along the wire.
But, if this were true, then the equation (1) does not hold because the integral of the electric field is 0. How can it account for the magnetic flux across the coil?
You are correct up to the point where you think the E field of all electrons points to the center. Actually, the electrons will all rush towards one end of the ring. There would then be an e field around the ring caused by the electrons, and an e field in the opposite direction caused by the EMF. When they will be equal, the current will stop and the ring will be like a capacitor under voltage.
ReplyDeleteI agree with you that "When they will be equal, the current will stop and the ring will be like a capacitor under voltage." In this case, the electric field on the surface of the wire is 0 along the wire.
DeleteBut, if this were true, then the equation (1) does not hold because the integral of the electric field is 0. How can it account for the magnetic flux across the coil?